Debugging Segmentation Faults

Generally, a segmentation fault is caused by trying to access a memory location you shouldn't. This can happen, for instance, if you declare an ...

Hello, I have this error Program received signal SIGSEGV: Segmentation fault - invalid memory reference. I believe it is due to the use of ...

Debugging Segmentation Faults. If a program gets a segmentation fault ( SIGSEGV ), it references a memory address outside of the memory available to it.

In Fortran programs, the most common bugs that cause segmentation faults are array bounds violations—attempts to write past the declared bounds ...

The code calls a subroutine that has a function(?) which get 'rec' from the user input, but that subroutine is pretty long so I just shortened to show error.

The problem comes from the size of the stack used by some compilers by default ( ifort ) or by some others when they optimise the compilation ( gfortran -Ofast ...

One possible answer is that you have told the compiler to vectorize the loop, and that causes a seg fault due to fault memory access. When you ...

Depending on the compiler you're using try adding -g -fbacktrace (for gfortran/gnu compilers) which will help you narrow down the error, also - ...

The most common cause of this error is an array index being outside the declared range. This could occur from a miscalculation of an array index or the ...

One possible answer is that you have told the compiler to vectorize the loop, and that causes a seg fault due to fault memory access. When you ...